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Exponents/logarithms in modelling - Mathematics: Applications & Interpretation IB Study Notes

Exponents/logarithms in modelling - Mathematics: Applications & Interpretation IB Study Notes | Times Edu
IBMathematics: Applications & Interpretation~6 min read

Overview

# Exponents and Logarithms in Modelling This lesson explores exponential and logarithmic functions as essential tools for modelling real-world phenomena including population growth, radioactive decay, compound interest, and pH scales. Students learn to construct, interpret, and analyse exponential models of the form y = ka^x or y = Ae^(kx), apply logarithmic transformations to linearise data, and solve problems using both algebraic and graphical methods. This topic is fundamental to Paper 2 and the Internal Assessment, where candidates must demonstrate their ability to select appropriate models, use technology effectively, and interpret mathematical results in authentic contexts with consideration of validity and limitations.

Core Concepts & Theory

Exponential functions model situations where quantities grow or decay at rates proportional to their current value, expressed as f(x) = a·b^x where a is the initial value, b is the base (growth factor), and x is the independent variable (often time). When b > 1, we have exponential growth; when 0 < b < 1, we have exponential decay.

Logarithms are the inverse operations of exponents. If b^y = x, then log_b(x) = y. The natural logarithm uses base e (≈2.718): ln(x) = log_e(x). Key logarithm laws include:

  • Product Rule: log_b(xy) = log_b(x) + log_b(y)
  • Quotient Rule: log_b(x/y) = log_b(x) - log_b(y)
  • Power Rule: log_b(x^n) = n·log_b(x)
  • Change of Base: log_b(x) = ln(x)/ln(b)

Critical IB Connection: Linearization transforms exponential models into linear form. Taking logarithms of both sides of y = ab^x gives ln(y) = ln(a) + x·ln(b), creating a linear relationship between ln(y) and x.

The exponential model P(t) = P₀e^(kt) is fundamental, where P₀ is the initial quantity, k is the growth/decay constant (positive for growth, negative for decay), and t is time. The doubling time satisfies 2P₀ = P₀e^(kt_d), giving t_d = ln(2)/k. Similarly, half-life t_h = ln(2)/|k| for decay models.

Command words in IB include: model (create mathematical representation), determine (find specific values), interpret (explain meaning in context), and justify (provide mathematical reasoning).

Detailed Explanation with Real-World Applications

Population Growth: Bacterial colonies, human populations (under ideal conditions), and viral spread follow exponential models. Consider a bacteria population doubling every 3 hours. Starting with 100 bacteria, after t hours: P(t) = 100 × 2^(t/3). This models unrestricted growth until resources become limited.

Radioactive Decay: Carbon-14 dating uses exponential decay with a half-life of 5,730 years. If a fossil contains 25% of original Carbon-14, we solve 0.25 = e^(-kt) where k = ln(2)/5730. This gives t ≈ 11,460 years.

Financial Mathematics: Compound interest demonstrates exponential growth. An investment of £5,000 at 4% annual interest compounds to A = 5000(1.04)^t. After 10 years: A = £7,401.22. The continuous compounding formula A = Pe^(rt) models scenarios where interest compounds infinitely often.

Medicine: Drug concentration in bloodstream follows exponential decay. If a 100mg dose has a half-life of 6 hours, the model C(t) = 100e^(-kt) where k = ln(2)/6 ≈ 0.1155 predicts concentration at any time.

Think of exponential growth like a snowball rolling downhill — it starts small but accelerates rapidly as it gains mass. Each rotation adds proportionally more snow to its surface.

pH Scale and Logarithms: pH = -log₁₀[H⁺] converts hydrogen ion concentration to a manageable scale. A pH difference of 1 represents a 10-fold change in acidity. Lemon juice (pH 2) is 100 times more acidic than tomatoes (pH 4).

Sound Intensity: The decibel scale uses logarithms: L = 10log₁₀(I/I₀) where I₀ is the reference intensity. This compresses the enormous range of human hearing into a practical 0-140 scale.

Worked Examples & Step-by-Step Solutions

**Example 1**: A radioactive substance has a half-life of 8 days. If 200g remains after 20 days, determine the initial mass. *Solution*: Use *M(t) = M₀e^(-kt)* where *k = ln(2)/8 = 0.08664*. Substitute known values: *200 = M₀e^(-0.08664×20)* *200 = M₀e^(-1.7328)* → *200 = M₀(0.1768)* → *M₀ = 1,13...

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Key Concepts

  • Exponential Growth: When a quantity increases at a rate proportional to its current size, leading to rapid growth over time.
  • Exponential Decay: When a quantity decreases at a rate proportional to its current size, leading to rapid reduction over time.
  • Logarithm: The power to which a base must be raised to produce a given number; it's the inverse operation of exponentiation.
  • Modelling: Using mathematical equations and concepts to represent and predict real-world situations.
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Exam Tips

  • Always identify if the problem describes growth or decay first; this helps you choose the correct formula.
  • Remember that logarithms are used to solve for an unknown exponent (like time or rate) in an exponential equation.
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